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Your starting point here is the ph of the solution 1 therefore, moles of pb in pbcl (oh) is 0.712 pb > (a) with hcn the hcn adds across the α c=o group to form a cyanohydrin

Underbrace (ch_3cocooh)_color (red) (pyruvic acid) + hcn →. Pbcl (oh)=0.185/ (207.2+35.5+16+1)*1000 (1kg=1000g) = 0.712 (to 3s.f) pb2cl2co3=0.185/ (207.2*2+35.5*2+12+16*3)*1000 = 0.339 (to 3s.f) next, find the moles of pb from each compound The acid in excess is then titrated with n aoh (aq) of known concentration.we can thus get back to the concentration or molar quantity of m (oh)2.as it stands the question (and answer) are hypothetical.

Conjugates are basically the other term

For every acid, you have a conjugate base (that no longer has that extra h^+ ion), and for every base, you have a conjugate acid (that has an extra h^+ ion). The sodium ions remain in solution as spectator ions If xs sodium hydroxide is added the precipitate redissolves to give the soluble plumbate (ii) ion A simple way of writing this is

Since water is in excess, 67.7 g mgo are needed to produce 98.0 g mg(oh)_2 Balanced equation mgo(s) + h_2o(l)rarrmg(oh)_2(s) moles magnesium hydroxide start with the given mass of mg(oh)_2 and convert it to moles by dividing by its molar mass (58.319 g/mol) Since molar mass is a fraction, g/mol, we can divide by multiplying by the reciprocal of the molar mass, mol/g. As you know, ammonia is a weak base, which means that it does not ionize completely in aqueous solution

Simply put, some molecules of ammonia will accept a.

The correct answer is a) hydroxide, carbonate, and hydrogen carbonate Alkalinity is another word for basicity (the concentration of hydroxide ions) A) hydroxide ions oh⁻ are the strongest base you can have in water Carbonate ions and hydrogen carbonate ions also react with water to form hydroxide ions

Co₃²⁻ + h₂o ⇌ hco₃⁻ + oh⁻ hco₃⁻ + h₂o ⇌ h₂co₃ + oh⁻ b. Answer is 286g (3s.f) concept required Mole calculation first start off by finding the number of moles for both compounds

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