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Can someone give me some really hard intergrals to solve The discussion highlights that convenient split points are typically at the origin or at discontinuities, allowing for clearer limit evaluations I want to try moer

Do you know of any reference for elliptic integrals in general While it may seem tedious, dividing the integral at points of discontinuity ensures the existence of limits and prevents divergence There are doubtless entire monographs devoted to elliptic integrals, but one concise reference is

Handbook of mathematical functionsby abramowitz and stegun, chap

17 i happen to have a print copy (from 1968!) but you can find pdf versions floating around on the web Since i'm trying to make sense of the application of a concept, i figured i'd post this thread here If this belongs in the homework forum, i sincerely apologize For the longest time i would do integral problems in calculus

I figured i understood how to do them because after i finished. My teacher said it's okay to use it to check your answer during a test, so if you know how, please let me know Why is it that when we evaluate a surface integral of F(x, y ,z) over ds, where x = x(u, v) y = y(u, v) z = z(u, v) ds is equal to ||ru x rv|| da why don't we use the jacobian here when we change coordinate systems?

I was wondering,how do we calculate the perimeter of a region using integral calculus?i know that to calculate the area we have to draw the region and if we.

Homework statement i know that a single integral can be used to find the area under a y = f(x) curve, but above the x axis Correct me if this example of a double integral is invalid If i hold a piece of paper in mid air and it droops, the double integral will give me the volume of the object. Usually trig integrals need that, but even a simple integral like \int_ {0}^ {1} dx can go wrong if we multiply and divide by the same thing

Also most of the time we aren't just multiplying and dividing by a number, we do a variable For instance, to the above integral, if i go ahead and multiply and divide x (x/x) then that integral becomes. My question is, what's the proof to this? Splitting improper integrals is often necessary to handle discontinuities and infinite bounds effectively

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